SOLUTION: I have solved the first part of the problem but need help with the second! Assume that a surveyor stands at the top of a mountain that is “h” feet tall. If the distance (in fe

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Question 212932: I have solved the first part of the problem but need help with the second!

Assume that a surveyor stands at the top of a mountain that is “h” feet tall. If the distance (in feet) that he can see is defined by d = 3200.2 SQRT(h), then answer the following. (a) How far can the surveyor see from the top of a 2000-foot mountain? (b) How tall is the mountain, if the surveyor can see 15 miles? (Note: 1 mile equals 5280 feet.)
d=3200.2SQRT2000
d=3200.2(44.72
d=143117.29 ft

Thanks for the help!
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Ok on part 1 of the problem!
Part 2.
d+=+3200.2sqrt%28h%29 Substitute h = 15mi.(5280ft/mi.) = 79200feet.
79200+=+3200.2sqrt%28h%29 Divide both sides by 3200.2
24.75+=+sqrt%28h%29 Square both sides.
612.486+=+h
The mountain is 612.5 feet tall.