SOLUTION: Find the dimensions of a rectangle whose length is 40 inches more than its width and whose perimeter is 300 inches.

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Question 212629: Find the dimensions of a rectangle whose length is 40 inches more than its width and whose perimeter is 300 inches.
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
Find the dimensions of a rectangle whose length is 40 inches more than its width and whose perimeter is 300 inches.

Step 1. Let l = w+40 length of rectangle and let w be the width

Step 2. Let P = 300 inches be the perimeter. Perimeter means adding the 4 sides of a rectangle. So,

P=w%2B40%2Bw%2B40%2Bw%2Bw

P=4w%2B40%2B40

P=4w%2B80=300

Step 3. Subtract 80 to both sides of equation to get 4w by itself


P=4w%2B80-80=300-80

4w=220

Step 4. Divide 4 to both sides of equation

4w%2F4=220%2F4

w=+55+

Step 5. w = 55 is the width of the rectangle and length is 95 since

l=55+40=95

Check P=4w+80=4(55)+80=220+80=300 So w = 55 and l = 95 is the solution.

Hope the above steps were helpful. Good luck in your homework and studies!

Respectfully
Dr J

Hope you understood and followed the steps. Good luck in your studies. Dr J

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