SOLUTION: The student center contain 4800 square ft. and its length is 20 ft. longer than its width. What are the dimensions?

Question 201096: The student center contain 4800 square ft. and its length is 20 ft. longer than its width. What are the dimensions?
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let the length = L and the width = W.
The area of a rectangle is given by:
Substitute L = W+20 and A = 4800.
Simplify.
Subtract 4800 from both sides.
Solve by factoring.
Apply the zero product rule.
or so that...
or Discard the negative solution as width can only be positive.
The width is 60 feet and the length is 60+20 = 80 feet.

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