SOLUTION: Please help. An artist wants her painting to be in the shape of a golden rectangle. If the length of the painting is 36 inches, then what should be the width? L/W = W/L-W

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Question 178716: Please help.
An artist wants her painting to be in the shape of a golden rectangle. If the length of the painting is 36 inches, then what should be the width?
L/W = W/L-W
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
An artist wants her painting to be in the shape of a golden rectangle.
If the length of the painting is 36 inches, then what should be the width?
:
Using the Golden Rectangle ratio of width/length which ~ .618...:
.618 * 36 = 22.25 inches
:
Or you can solve the given equation
L%2FW = W%2F%28%28L-W%29%29
L = 36, Find W
36%2FW = W%2F%28%2836-W%29%29
Cross Multiply
W^2 = 36(36-W)
:
W^2 = 1296 - 36W
:
W^2 + 36W - 1236 = 0
:
Using the quadratic formula, the positive solution should = 22.25" also