Question 178162: A storekeeper goes to the bank to get $10 worth of change. She requests twice as many quarters as half dollars, twice as many dines as quarters, three times as many nickels as dimes, and no pennies or dollars. How many of each coin did the storekeeper get?
What I have done so far:
q (quarters) h(half dollars) d(dimes) n(nickels)
Quarters = q
Half dollars = 2q
Dimes = 3q
Nickels = 9q
.50(2q) + .25(q)+ .10(3q) + .05(9q) = 10
q + .25q + .30q + .45q = 10
10q = 10
q=1
But, that doesn't make sense.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! A storekeeper goes to the bank to get $10 worth of change. She requests twice as many quarters as half dollars, twice as many dines as quarters, three times as many nickels as dimes, and no pennies or dollars. How many of each coin did the storekeeper get?
What I have done so far:
q (quarters) h(half dollars) d(dimes) n(nickels)
Quarters = q
Half dollars = 2q
Dimes = 3q
Nickels = 9q
.50(2q) + .25(q)+ .10(3q) + .05(9q) = 10
q + .25q + .30q + .45q = 10
10q = 10
q=1
But, that doesn't make sense.
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Do it in cents.
q (quarters) h(half dollars) d(dimes) n(nickels)
q = 2h
d = 4h
n = 12h
Then,
50h + 25*2h + 10*4h + 5*12h = 1000
200h = 1000
h = 5
You can take it from there
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