SOLUTION: find two numbers whose sum is 30, such that the sum of the square of one number plus ten times the other number is a minimum. Thank you in advance for helping me with this funct

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Question 175552This question is from textbook college algebras
: find two numbers whose sum is 30, such that the sum of the square of one number plus ten times the other number is a minimum.
Thank you in advance for helping me with this function.
This question is from textbook college algebras

Answer by eggsarecool(46) About Me  (Show Source):
You can put this solution on YOUR website!
The first part of this problem is interpretation.
two numbers whose sum is 30 means x+%2B+y+=+30 , since we don't know wither number we need two variables.
the square of one number plus ten times the other number means f%28x%29=x%5E2+%2B+10y I am calling the equation f(x) so we have a name for it.
The next thing to remember is that to find the minimum of a function you take the derivative(calculus), set the derivative equal and solve.
Since they wanted a minimum for "such that the sum of the square of one number plus ten times the other number is a minimum" we need to take the derivative of f(x)
This presents a small problem since you can only have one variable when taking the derivative. We solve this by rewriting x+%2B+y+=+30 as y=30-x
We then substitute this into f(x), giving us +f%28x%29=x%5E2+%2B+10%2830-x%29 I replaced the y with +30-x.
We now have f%28x%29=+x%5E2+%2B300-10x
The next step is to take to derivative. +%28d%2Fdx%29+f%28x%29=2x-10+, the derivative of x%5E2 was 2x, the derivative of 300 since t is just a number is 0, and the derivative of -10x is -10, giving you 2x-10 as your derivative
You then take 2x-10=0 and solve
2x=10
and
x=10%2F2=5
Plugging back into x%2By=30 you now have 5%2By=30 giving you y=25
So the answer is x=5 and y=25 will give you the minimum