Question 170506: x varies directly as the square of s and inversely as t. How does x change when s is doubled? When both s and t are doubled? Found 2 solutions by stanbon, Mathtut:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! x varies directly as the square of s and inversely as t.
x = k[s^2/t]
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How does x change when s is doubled?
x = k[(2s)^2/t] = 4k[s^2/t]
doubling s quadruples x
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When both s and t are doubled?
x = k[(2s)^2/(2t)]
x = 4ks^2/(2t)
x = 2ks^2/t
doubling s and t doubles x
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Cheers,
Stan H.
You can put this solution on YOUR website! remember when a constant like x in our case varies directly with another variable,s squared in our case it takes on this form and when a constant like x varies indirectly with t it takes on this form xt=k
: together we have xt/s^2=k or
:
so we have when s is doubled we have or meaning x increases by 4 when s is doubled.
:
when s and t are doubled we have or
meaning x doubles when s and t are doubled
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