SOLUTION: 545 g of Ar gas are contained in a 13.3 L pressure vessel at at temperature of 90°C. What is the pressure exerted by the gas? (VII-1) ____atm

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Question 169512: 545 g of Ar gas are contained in a 13.3 L pressure vessel at at temperature of 90°C. What is the pressure exerted by the gas? (VII-1)
____atm
Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!
.
This follows the Ideal Gas Law -----> PV=nRT, Working Eqn
where--->
Highlighted above is not given, so we have to calculate:
Look thru Table of Elements or Periodic Table and you find Molecular Weight for Argon: 39.948%28g%2Fmol%29
So, n=m%2FMW=545%28cross%28g%29%29%2F%2839.948%2Across%28g%29%2Fmol%29
n=13.64mol, Subst. in our Working Eqn:
P%2813.3%29=%2813.64%29%280.0821%29%2890%2B273.15%29
P%2813.3%29=406.67 ------> P%2Across%2813.3%29%2Fcross%2813.3%29=cross%28406.67%2930.58%2Fcross%2813.3%29
highlight%28P=30.58atm%29, Answer
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Thank you,
Jojo