SOLUTION: the population of glenbrook is 375000 and is increasing at the rae of 2.25% per year. predict when the population will be 1 million. i neeed help. please answer this....

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Question 157665: the population of glenbrook is 375000 and is increasing at the rae of 2.25% per year. predict when the population will be 1 million.
i neeed help. please answer this....
Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!
Population=P=375000
Rate=R=%280.0225%2A375000%29%2Fyear=8437.50%2Fyear
ProjectedPopulation=PP=1000000 ------------> in n years
Putting into equation:
PP=P%2BR -----------------------------> working eqn
1000000=375000%2B%288437.50%2Fcross%28year%29%29%28n%28cross%28years%29%29%29
%281000000-375000%29%2F8437.50=n
n=74.07407407years ---------> no. of years when popul'n will be 1,000,000
Or,
74years and %280.07407407%29%28cross%28year%29%29%2A%2812months%2Fcross%28year%29%29=0.8888months
Or,
74years and %280.8888888%29%28cross%28month%29%29%2A%2830days%2Fcross%28month%29%29=26.66666days
Or,
74years,26days and %280.66666%29%28cross%28day%29%29%2A%2824hours%2Fcross%28day%29%29=16hours
In doubt? Go back working eqn:

1000000=375000%2B625000
1000000=1000000
thank you,
Jojo