SOLUTION: If a ball is tossed in the air from a height of 6 feet with a velocity pf 32 feet per second, then its altitude at time t(seconds) can be described by the function A(t) = -16t2 + 3

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Question 156875: If a ball is tossed in the air from a height of 6 feet with a velocity pf 32 feet per second, then its altitude at time t(seconds) can be described by the function A(t) = -16t2 + 32r + 6. Find the altitude of the ball at 2 seconds.
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
To find the altitude, A, when after two seconds (t=2), substitute t = 2 into the given equation and solve for the altitude, A.
A%28t%29+=+-16t%5E2%2B32t%2B6 Substitute t =2.
A%282%29+=+-16%282%29%5E2%2B32%282%29%2B6
A%282%29+-64%2B64%2B6 Simplify.
A%282%29+=+6
The altitude at 2 seconds is 6 feet, so the ball is on the way down and, at 2 seconds, it is at the same altitude as when it was initially tossed.