SOLUTION: A standard 55 gallon drum is holding oil. A portion of the oil is removed. A stick with inch measurements is placed in the drum. The remaining level is 2 7/8 inches. Determine a

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Question 1210578: A standard 55 gallon drum is holding oil. A portion of the oil is removed. A stick with inch measurements is placed in the drum. The remaining level is 2 7/8 inches. Determine amount (gallons) remaining in drum.
Check my calculations, please.
Dimensions:
Diameter; 22.5"
Height; 33.5"
Drum is cylindrical, and standing vertical.
Volume formula; pi * r^2 * h.
3.1416 * 16.75 * 16.75 * 2 7/8 (2.875) = 2534.06 cu. in.
2534.06 / 231 = 10.969 = 11 gal.
Where am I correct ? Answer given is less.
Found 3 solutions by josgarithmetic, timofer, ikleyn:
Answer by josgarithmetic(39734)   (Show Source):
You can put this solution on YOUR website!
....., t the formula relies on SQUARING the radius. Notice, in there.

To put in the number values directly, full drum volume in cubic inches should be

cubic inches, not rounding too much...

The level being down to inch,

cubic inches.

You can look for the conversion to gallons.

about 4.95 gallons

Answer by timofer(144)   (Show Source):
You can put this solution on YOUR website!
Accepting the inside volume capacity is 55 gallons( the assumption could be wrong), then the amount filled at level of
2 and 7/8 inches should be gallons.
(used online calculator)

Answer by ikleyn(53618)   (Show Source):
You can put this solution on YOUR website!
.

In your calculations, the number 16.75 is irrelevant. It is the source of your error.

Instead, you should use the radius value 22.5/2 == 11.25 inches.