SOLUTION: (666667 * 222222)-(333333 * 444444) The answer should be solved without working it out full.

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Question 1210276: (666667 * 222222)-(333333 * 444444)
The answer should be solved without working it out full.

Found 5 solutions by ikleyn, hudikamo, greenestamps, mccravyedwin, Edwin McCravy:
Answer by ikleyn(52778) About Me  (Show Source):
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.

  (666667 * 222222)-(333333 * 444444) = 

= ((666666+1) * 222222) - (333333 * 444444) =

= (666666 * 222222) - (333333 * 444444) + 1 * 222222 = 

= (2 * 333333 * 222222) - (333333 * 2 * 222222) + 222222 =

   cancel equal terms with the opposite signs and continue

= ( 0 ) + 222222 = 222222.    ANSWER

Solved.



Answer by hudikamo(4) About Me  (Show Source):
You can put this solution on YOUR website!
(666667 * 222222)-(333333 * 444444)
(666667 * 222222) -> (666666 * 222222) + (1 * 222222)
(666666 * 222222) -> (2 * 333333) * 222222 [a]
(333333 * 444444) -> (2 * 222222) * 333333 [b]
[a] == [b] therefore [a] - [b] = 0
Leftover (1 * 222222)
0 + 222222 = 222222

Answer by greenestamps(13198) About Me  (Show Source):
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Observe that 444444 is 222222*2.

Then employ a useful mental math technique of performing a multiplication of two numbers by doubling one of them and cutting the other in half:

333333 * 444444 = 666666 * 222222

Then the expression to be evaluated is

(666667 * 222222) - (666666 * 222222) = (1) * (222222) = 222222

ANSWER: 222222


Answer by mccravyedwin(406) About Me  (Show Source):
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
Make it even shorter:
(666667 * 222222)-(333333 * 444444)
matrix%281%2C2%2CLet%2CN=111111%29%29
666667+=+666666%2B1+=+6%28111111%29%2B1=6N%2B1
222222+=+2%28111111%29=2N
444444+=+4%28111111%29=4N
%28%286N%2B1%5E%22%22%29%5E%22%22+%2A+2N%5E%22%22%29-%283N%5E%22%22+%2A+4N%29
12N%5E2%2B2N-12N%5E2
2N
2%28111111%29
222222

Edwin