Question 1209840: I came across the following question today:
A rectangular parcel of length x metres, width k metres and height k metres is to be sent through the post. The total length and girth of the parcel is to be exactly 2 metres. Show that the volume of the parcel is
V = x/16(2-x)^2
What I do not understand is, is the x in the volume equation the length of the parcel (ie 2m) or a different variable?
Also, does (2-x)^2 mean
(2-x)(2-x) ie 4-4x+x^2?
Found 2 solutions by ikleyn, math_tutor2020:
Answer by ikleyn(52777)   (Show Source):
You can put this solution on YOUR website! .
I came across the following question today:
A rectangular parcel of length x metres, width k metres and height k metres is to be sent through the post. The total length and girth of the parcel is to be exactly 2 metres. Show that the volume of the parcel is
V = x/16(2-x)^2
What I do not understand is, is the x in the volume equation the length of the parcel (ie 2m) or a different variable?
Also, does (2-x)^2 mean
(2-x)(2-x) ie 4-4x+x^2?
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As I read this post, I see that this assignment is ILLOGICAL and is as far
from to be a true Math problem as the ground is far from heavens.
It has nothing in common with Math problems, as people traditionally understand this conception of Math problems.
Regarding your last question, whether does (2-x)^2 mean (2-x)(2-x) ie 4-4x+x^2,
the answer is " Yes ".
Answer by math_tutor2020(3816)  (Show Source):
You can put this solution on YOUR website!
x = length
k = width
k = height
volume of rectangular block = length*width*height
V = x*k*k
V = x*k^2
If length + width = 2 meters, then,
x+k = 2
k = 2-x
So,
V = x*k^2
V = x*(2-x)^2
V = x*(2-x)(2-x)
V = x*(4-4x+x^2)
V = x^3-4x^2+4x
I don't know where your textbook got the x/16 from.
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