SOLUTION: Hi Mr Jones has some notes. 1/5 of them are 2 dollar notes. 3/8 of the remainder are 10 dollar notes. The remaining notes are 5 dollar notes. The total sum he has $295 . How many

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Question 1208132: Hi
Mr Jones has some notes. 1/5 of them are 2 dollar notes. 3/8 of the remainder are 10 dollar notes. The remaining notes are 5 dollar notes. The total sum he has $295 . How many 10 dollar notes does he have.
Found 3 solutions by josgarithmetic, greenestamps, MathTherapy:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Some how I do not think this is a very neat way to tabulate the described information: 
NOTE, $2              n/5

NOTE, $5               (3/8)(n-(n/5))

NOTE, $10            n-(n/5+(3/8)(n-(n/5)))

TOTAL NOTES              n


Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


1/5 of the notes are $2 notes, so 4/5 of the notes are $5 or $10 notes.

3/8 of those remaining 4/5 of the notes are $10 notes.
(3/8)*(4/5) = 12/40 = 3/10.
3/10 of the notes are $10 notes.

Together the $2 notes and the $10 notes are 1/5 + 3/10 = 5/10 = 1/2 of the notes, so 1/2 of the notes are $5 notes.

The fractions of the total number of notes for the three denominations are then
$2: 1/5 = 2/10
$10: 3/10
$5: 1/2 = 5/10

Seeing the common denominator 10 in those fractions, let the numbers of notes of the three denominations be
2x = # of $2 notes
3x = # of $10 notes
5x = # of $5 notes

Now use those expressions to write and solve an equation that says the total amount is $295.

2x%282%29%2B3x%2810%29%2B5x%285%29=295
4x%2B30x%2B25x=295
59x=295
x=295%2F59=5

ANSWER: the number of $10 notes is 3x = 3(5) = 15

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!
Hi
Mr Jones has some notes. 1/5 of them are 2 dollar notes. 3/8 of the remainder are 10 dollar notes. The remaining notes are 5 dollar notes. The total sum he has $295 . How many 10 dollar notes does he have.

Let number of notes be N
Then number of $2 notes = matrix%281%2C5%2C+1%2F5%2C+of%2C+N%2C+%22=%22%2C+N%2F5%29, and remaining notes = 
Also, number of $10 notes = 
Remaining notes (number of $5 notes) = 
                Amount in $2 notes: matrix%281%2C3%2C+2%28N%2F5%29%2C+%22=%22%2C+2N%2F5%29
             Amount in $10 notes: matrix%281%2C3%2C+10%283N%2F10%29%2C+%22=%22%2C+3N%29
                Amount in $5 notes: matrix%281%2C3%2C+5%28N%2F2%29%2C+%22=%22%2C+5N%2F2%29
                              Total amount: $295

                    We now get: matrix%281%2C3%2C+2N%2F5+%2B+3N+%2B+5N%2F2%2C+%22=%22%2C+295%29
                             4N + 30N + 25N = 2,950 ----- Multiplying by LCD, 10
                                        59N = 2,950
                     Number of notes, or matrix%281%2C5%2C+N%2C+%22=%22%2C+%222%2C950%22%2F59%2C+%22=%22%2C+50%29
                   Number of $10 notes: