Question 1207381: A car dealer, at a year-end clearance, reduces the list price of last year’s models by 15%.If a certain four-door model has a discounted price of $8000,what was its list price? How much can be saved by purchasing last year’s model?
I need the correct equation set up.
Thanks.
Answer by ikleyn(52776) (Show Source):
You can put this solution on YOUR website! .
Let x be the original price before the discount.
Then the governing equation to find x from the problem is
(1-0.15)x = 8000,
or, which is the same
0.85x = 8000.
It gives x = = 9411.764706.
Rounded to the closest dollar, it is x = $9,412.
Buying a discounted car, a buyer saves $9,412 - $8000 = $1,412.
Solved.
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Comment from student : You provided two equations in your reply. I have two questions about the first equation.
You said: (1-0.15)x = 8000 Questions: 1. What information in the word problem indicates to subtract 15% from 1?
2. Does the number 1 inside the parentheses represent 100%? If so, you did 100% - 15% = 85% = 0.15. Yes?
My response: Your suggestions/(guesses) are correct.
I am very glad that by straining your mind, you were able to figure this out on your own.
It is my major goal at this forum - to awaken the brain of visitors.
Also, I thought that it is clear and obvious to as a sunny day - it is why I didn't go into further explanations.
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