SOLUTION: Hi
Haresh gave 1/6 of his money to Jane. He spent $8 less than 1/3 of the remaining money on books. Haresh had $68 left. How much did he have at first.
My son solved it by worki
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Haresh gave 1/6 of his money to Jane. He spent $8 less than 1/3 of the remaining money on books. Haresh had $68 left. How much did he have at first.
My son solved it by worki
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Question 1206129: Hi
Haresh gave 1/6 of his money to Jane. He spent $8 less than 1/3 of the remaining money on books. Haresh had $68 left. How much did he have at first.
My son solved it by working backwards, can you show how to solve it algebraically.
After he gave 1/6 of it to Jane, the number he had left was .
1/3 of what he had left was
$8 less than what he had left was
After spending that amount, the amount he had left was
The amount he had left was $68:
ANSWER: $108
CHECK:
start: $108
give away 1/6 = $18; $90 left
spent $8 less than 1/3 of what he had left = (1/3)$90-$8 = $30-$8 = $22
amount he finished with: $90-$22 = $68
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Haresh gave 1/6 of his money to Jane. He spent $8 less than 1/3 of the remaining money on books.
Haresh had $68 left. How much did he have at first.
My son solved it by working backwards, can you show how to solve it algebraically.
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Let x be the amount Haresh had at first.
After Haresh gave 1/6 of his money to Jane, his remaining amount is .
He spent on books = .
After that, his remaining money is - = .
This amount is 68 dollars. So, the equation is
= 68.
To solve, multiply all the terms by 18
10x + 8*18 = 18*68
10x = 18*68-8*18
10x = 1080
x = 1080/10 = 108.
ANSWER. Haresh had $108 at first.