SOLUTION: Mr. Smith had just finished baking a cake for the mathematicians’ banquet. The cake was specially designed in the shape of a cube. In the process of carrying the cake to the fros

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Question 1206044: Mr. Smith had just finished baking a cake for the mathematicians’ banquet. The cake was specially designed in the shape of a cube. In the process of carrying the cake to the frosting table, Mr. Smith suddenly slipped and the cube-cake went sailing into the vat of chocolate frosting. Mr. Smith thought quickly and then yelled “FIRE!” (He knew that no one would come to help if he yelled, “Chocolate”).
Almost immediately help arrived and the cake was fished out of the chocolate. Fortunately, the cube-cake was still in one piece, but was now frosted on all sides.
Mr. Smith proceeded to the banquet hall with his unusually frosted cake in hand.
The mathematicians were delighted when they saw the cube-cake with all of the frosting. They asked Mr. Smith to stay and cut the cake.
One of the mathematicians, Mrs. Hayne suggested that the cake be cut into cube-shaped pieces, all pieces the same size. Mr. Smith agreed, but before cutting the cake he turned to Mrs. Hayne and asked how many mathematicians would like a piece without frosting, a piece with only one side frosted, a piece with exactly two sides frosted, or a piece with three sides frosted.
Being a mathematician, Mrs. Hayne responded, “Cut the cake so that the number of pieces without frosting is equal to eight times the number of pieces that have frosting on three sides. You will then have enough of each type of piece to satisfy everyone, with nothing left over.”
Please answer the following questions.
How many mathematicians attended the banquet?
How many mathematicians were served a piece of cake without frosting? How many mathematicians requested a piece with only one side frosted? How many were served a piece of cake with exactly two sides frosted? How many requested a piece with three sides frosted?

Answer by math_tutor2020(3816) About Me  (Show Source):
You can put this solution on YOUR website!

Grab a Rubik's cube to help visualize what's going on.
Although the cake won't be split into 27 smaller cubes, it's a similar idea.
The 8 corner pieces represent the pieces that have 3 sides frosted.

Since the "number of pieces without frosting is equal to eight times the number of pieces that have frosting on three sides", this means there will be 8*8 = 64 pieces without frosting.

This inner unfrosted block must be 4 units in side length because 4*4*4 = 64
Or you could say root%283%2C64%29+=+64%5E%281%2F3%29%5E%22%22+=+4 units

Let's look at a birds-eye-view of the cake.

The pieces marked in yellow are the 4 corners for this top face (each corner gets 3 faces frosted).
There are 8 of these pieces as mentioned earlier. 4 for the top and 4 for the bottom.

The pieces shaded gray will get 1 face painted. There are 4*4 = 16 pieces shown in the diagram. With 6 faces to the original larger cube, that's 6*16 = 96 pieces that get 1 face painted.

The unshaded parts of the diagram represent pieces of cake that get 2 faces painted.
There are 4 white little squares along any edge and 12 edges in any cube, so 12*4 = 48 pieces of cake that get 2 faces painted.

Notice the overall cube has side length 6 units, so there are 6^3 = 6*6*6 = 216 pieces total

Summary:
64 pieces with no frosting
96 pieces with one face painted
48 pieces with two faces painted
8 pieces with three faces painted
64+96+48+8 = 216 pieces total. This checksum helps verify the answer.


Edit:
Here's what the 3D view would look like