SOLUTION: A mixture of sand and gravel are in two piles. Ratio of sand to gravel is 1:3 in first pile, and 3:5 in second. 24 cu. yds. from first are mixed with 40 cu. yds. from second. De
Algebra ->
Customizable Word Problem Solvers
-> Misc
-> SOLUTION: A mixture of sand and gravel are in two piles. Ratio of sand to gravel is 1:3 in first pile, and 3:5 in second. 24 cu. yds. from first are mixed with 40 cu. yds. from second. De
Log On
Question 1203899: A mixture of sand and gravel are in two piles. Ratio of sand to gravel is 1:3 in first pile, and 3:5 in second. 24 cu. yds. from first are mixed with 40 cu. yds. from second. Determine cu. yds. of sand in resulting mixture.
Unsure how to solve. Found 2 solutions by greenestamps, josgarithmetic:Answer by greenestamps(13216) (Show Source):
The ratio of sand to gravel in the first pile is 1:3, which means 1/4 is sand and 3/4 is gravel. 24 cubic feet are taken from this pile; the amount of sand in those 24 cubic feet is 1/4 of 24 cubic feet, which is 6 cubic feet.
The ratio of sand to gravel in the second pile is 3:5, which means 3/8 is sand and 5/8 is gravel. 40 cubic feet are taken from this pile; the amount of sand in those 40 cubic feet is 3/8 of 40 cubic feet, which is 15 cubic feet.
ANSWER: The amount of sand in the mixture is 6+15 = 21 cubic feet.