SOLUTION: Four times the sum of twice the number and 7 exceeds the value of the number by 70. What is the number?

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Question 1202551: Four times the sum of twice the number and 7 exceeds the value of the number by 70. What is the number?
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Exactly as literally described!

For the number being called n,
4%282n%2B7%29-n=70.



6

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Beginning algebra students often have difficulty translating the words into algebraic language....

"four times..." ---> we are multiplying what comes next by 4 ---> 4(...)

"four times the sum of ..." ---> what we are multiplying by 4 is the sum of (at least) two things ---> 4(...+...)

"four times the sum of twice the number and 7..." ---> 4(2x+7)

"four times the sum of twice the number and 7 exceeds the value of the number by 70"

Translating "exceeds" into mathematical language, this means that expression is 70 more than the number itself:

"four times the sum of twice the number and 7 is 70 more than the number" ---> 4(2x+7) = x+70

ANSWER: 4(2x+7 = x+70