SOLUTION: a ball is thrown across a playing field. it’s path is by the equation y=-0.005x^2 +x+5 where x is the distance the ball has traveled horizontally. and y is it’s height above gr
Algebra ->
Customizable Word Problem Solvers
-> Misc
-> SOLUTION: a ball is thrown across a playing field. it’s path is by the equation y=-0.005x^2 +x+5 where x is the distance the ball has traveled horizontally. and y is it’s height above gr
Log On
Question 1197419: a ball is thrown across a playing field. it’s path is by the equation y=-0.005x^2 +x+5 where x is the distance the ball has traveled horizontally. and y is it’s height above ground level, both measured in feet. what is the maximum height attained by the ball? how far has it traveled horizontally when it hits the ground Found 2 solutions by Alan3354, ewatrrr:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! a ball is thrown across a playing field. it’s [sic] path is by the equation y=-0.005x^2 +x+5 where x is the distance the ball has traveled horizontally. and y is it’s [sic] height above ground level, both measured in feet. what is the maximum height attained by the ball? how far has it traveled horizontally when it hits the ground
-------------------------
it's = it is
=======================
y=-0.005x^2 +x+5 is a parabola
The vertex is at x = -b/2a = -1/-0.01 = 100
Sub 100 for x:
y = -0.005*10000 + 100 + 5 = 155 feet, the max height
=======================
y=-0.005x^2 +x+5
Find x when y = zero
-0.005x^2 +x+5 = 0
y=-0.005x^2 +x+5 (max at x = 100) y' = 0 ⇒ -.01x + 1 = 0 , x = 100
maximum P(100,55)
what is the maximum height attained by the ball?
Can see from graph travels 'approximately' from -5 to 205 0r ~210ft
Recommend using a Graphing software as a visual aid and calculator
FREE graphing software is available at http://www.padowan.dk.com
Below a screenshot of y=-0.005x^2 +x+5 using that software:
Using its 'evaluate' feature can also give a closer approximation to x-intercepts
.