SOLUTION: there were some apple pies and lemon pies pies in two boxes,A and B .box A had 40% of the total number of pies.box B had 12 apple pies.if 75% of the pies in box B were lemon pies,w

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: there were some apple pies and lemon pies pies in two boxes,A and B .box A had 40% of the total number of pies.box B had 12 apple pies.if 75% of the pies in box B were lemon pies,w      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1197118: there were some apple pies and lemon pies pies in two boxes,A and B .box A had 40% of the total number of pies.box B had 12 apple pies.if 75% of the pies in box B were lemon pies,what was the total number of pies in both boxes?
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


40% of the pies are in box A, so 60% are in box B. Given that ratio 40:60 = 2:3,

let 2x = # of pies in box A
let 3x = # of pies in box B

75% of the pies in box B are lemon, so 25% of them (i.e., 1/4 of them) are apple. Since the 12 apple pies in box B are 1/4 of the total number of pies in box B, the number of pies in box B is 12*4 = 48. Then we have

3x = 48
x = 16

And the total number of pies in the two boxes is

2x+3x = 5x = 80

ANSWER: 80