SOLUTION: Francis,Philip and Jamie had twenty-cent,fifty-cent and one-dollar coins respectively.Franci had five times as many coin as Jamie.Philip had half the number of coins that Jamie had

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Question 1197116: Francis,Philip and Jamie had twenty-cent,fifty-cent and one-dollar coins respectively.Franci had five times as many coin as Jamie.Philip had half the number of coins that Jamie had.if Philip had 27 fewer coins than Francis,how much money did they have altogether?
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Not the only way, but .....
PEOPLE       COIN TYPE       HOW MANY COIN
Francis         0.25              5j
Philip          0.50              j/2
Jamie           1.00              j

highlight_green%285j-j%2F2=27%29

10j-j=54

9j=54

j=6-------------use this now to find how much MONEY was their total.

Answer by greenestamps(13198) About Me  (Show Source):
You can put this solution on YOUR website!


The setup shown by the other tutor is fine; I personally would use the given information to set it up differently to avoid needing fractions or decimals.

The given information tells us that Philip had the smallest number of coins, so

let x = # of coins Philip had
then 2x = # of coins Jamie had (Philip had half as many as Jamie, so Jamie had twice as many as Philip)
and 10x = # of coins Francis had (5 times as many as Jamie)

Philip has 27 fewer coins than Francis:

10x-x = 9x = 27
x = 3

The amounts they each had....
Philip: x = 3 50-cent coins = $1.50
Jamie: 2x = 6 1-dollar coins = $6.00
Francis: 10x = 30 20-cent coins = $6.00

The total amount: $1.50+$6.00+$6.00 = $7.50

ANSWER: $7.50