SOLUTION: a grocer bought some oranges at a cost of 8 for 96 cents and then 2/3 times as many at a cost of 6 for 1.02. In order to make a profit 50%, he must sell all of them at a price of a

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Question 1196789: a grocer bought some oranges at a cost of 8 for 96 cents and then 2/3 times as many at a cost of 6 for 1.02. In order to make a profit 50%, he must sell all of them at a price of a dozen for $m. Find the value of m in dollars.
Found 3 solutions by greenestamps, josgarithmetic, MathTherapy:
Answer by greenestamps(13198) About Me  (Show Source):
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The first batch cost him 96/8 = 12 cents each; the second batch cost him 102/6 = 17 cents each.

Using the fact that the number in the second batch was 2/3 the number in the first...
let 3x = # in first batch
then 2x = # in second batch

The total cost to him in cents was

3x%2812%29%2B2x%2817%29=36x%2B34x=70x

The average cost to him for each orange was then that total cost, divided by the total number of oranges:

%2870x%29%2F%285x%29=14

The oranges cost him, on average 14 cents each; to make a profit of 50%, he needs to sell them at 21 cents each, which means 12(21) = 252 cents or $2.52 per dozen.

ANSWER (price per dozen in dollars): 2.52


Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
PRICE              QUANTITY          COST

8 for 96c           (3/2)n          (0.96/8)(3/2)n

6 for 102c           n               (1.02/6)n

The cost for the first two purchases
%280.96%2F8%29%283%2F2%29n%2B%281.02%2F6%29n
%280.48%2F8%293n%2B0.17n
0.18n%2B0.17n
0.35n ---------------dollars total the two first purchases

Quantity bought, first two purchases
%283%2F2%29n%2B%282%2F2%29n
%285%2F2%29n----------------- how many each bought, first two purchases

PRICE EACH first two purchases
%280.35n%29%2F%28%285%2F2%29n%29
0.35%282%2F5%29
highlight%280.14%29----------THE EFFECTIVE PRICE EACH in the two first purchases

You could find the value for %285%2F2%29n on the way toward answering the question, about selling those to get 50% profit.

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

a grocer bought some oranges at a cost of 8 for 96 cents and then 2/3 times as many at a cost of 6 for 1.02. In order to make a profit 50%, he must sell all of them at a price of a dozen for $m. Find the value of m in dollars.
Let N be the number of oranges purchased 1st
Then amount paid for the 1st purchase = matrix%281%2C3%2C+%28.96%2F8%29N%2C+%22=%22%2C+.12N%29
With matrix%281%2C5%2C+2%2F3%2C+of%2C+%22N%2C%22%2C+or%2C+2N%2F3%29 being the amount purchased after, the amount paid for the 2nd purchase = 

With sale price of $m per dozen, each orange was sold for m%2F12

    Total number of oranges purchased: matrix%281%2C5%2C+N+%2B+2N%2F3%2C+%22=%22%2C+%283N+%2B+2N%29%2F3%2C+%22=%22%2C+5N%2F3%29

Total cost of 5N%2F3 oranges: 

To realize a 50% profit, we then get: matrix%281%2C3%2C+%28m%2F12%29%285N%2F3%29%2C+%22=%22%2C+1.5+%2A+%28.7N%2F3%29%29