SOLUTION: a grocer bought some oranges at a cost of 8 for 96 cents and then 2/3 times as many at a cost of 6 for 1.02. In order to make a profit 50%, he must sell all of them at a price of a
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Question 1196789: a grocer bought some oranges at a cost of 8 for 96 cents and then 2/3 times as many at a cost of 6 for 1.02. In order to make a profit 50%, he must sell all of them at a price of a dozen for $m. Find the value of m in dollars. Found 3 solutions by greenestamps, josgarithmetic, MathTherapy:Answer by greenestamps(13198) (Show Source):
The first batch cost him 96/8 = 12 cents each; the second batch cost him 102/6 = 17 cents each.
Using the fact that the number in the second batch was 2/3 the number in the first...
let 3x = # in first batch
then 2x = # in second batch
The total cost to him in cents was
The average cost to him for each orange was then that total cost, divided by the total number of oranges:
The oranges cost him, on average 14 cents each; to make a profit of 50%, he needs to sell them at 21 cents each, which means 12(21) = 252 cents or $2.52 per dozen.
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a grocer bought some oranges at a cost of 8 for 96 cents and then 2/3 times as many at a cost of 6 for 1.02. In order to make a profit 50%, he must sell all of them at a price of a dozen for $m. Find the value of m in dollars.
Let N be the number of oranges purchased 1st
Then amount paid for the 1st purchase =
With being the amount purchased after, the amount paid for the 2nd purchase =
With sale price of $m per dozen, each orange was sold for
Total number of oranges purchased:
Total cost of oranges:
To realize a 50% profit, we then get: