Question 1189241: In a school of 970 students, all of them voted on two issues. 390 students voted in favour of banning cell phones, and 930 students voted in favour of having a school dance. Just 20 students voted against both issues. How many students voted in favour of both proposals
Answer by ikleyn(52776) (Show Source):
You can put this solution on YOUR website! .
In a school of 970 students, all of them voted on two issues.
390 students voted in favor of banning cell phones, and 930 students voted in favor of having a school dance.
Just 20 students voted against both issues. How many students voted in favor of both proposals
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In this problem, we have a universal set W of all 970 students.
We also have three subsets: B (banning) of 390 students;
D (dance) of 930 students,
and A (against both) of 20 students.
Notice that the sub-sets B and D may have non-empty intersection; while the sub-set A is DISJOINT from both B and D.
THEREFORE, the union of B and D has 970 - 20 = 950 students.
So, we can write n(B U D) = n(B) + n(D) - n(B & D), or
950 = 390 + 930 - n(B & D).
From this equation, you get the ANSWER to the problem's question n(B & D) = 390 + 930 - 950 = 370.
ANSWER. 370 students voted in favor of both proposals.
Solved and thoroughly explained.
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