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If speed is increased by 20 percent, a person arrives 15 minutes earlier.
What is the regular time taken by the person.
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Let "d" be the distance, let "t" be the regular (= the scheduled) travel time (in minutes), and let "u" be the regular speed.
Then the increased speed is 1.2u, and reduced traveled time is t-15 minutes.
We have two equations
= t (1)
and
= t - 15 (2)
From equation (2), we have
= 1.2*(t-15).
In this equation, replace its left side by t, based on equation (1).
You will get then simple linear equation for the single unknown t
t = 1.2*(t-15).
Simplify and find t
t = 1.2t - 18
18 = 1.2t - t
18 = 0.2t
t = = = 90 minutes.
ANSWER. The regular (=the scheduled) travel time is 90 minutes.
Solved.