SOLUTION: find a 2 digit number whose tens digit is 3 less than the units digit. The orginal number is 6 more than 4 times the sum of the digit

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Question 118600: find a 2 digit number whose tens digit is 3 less than the units digit. The
orginal number is 6 more than 4 times the sum of the digit

Answer by wgunther(43) About Me  (Show Source):
You can put this solution on YOUR website!
So, let a be the tens digit, and b be the unit digit.
a+3=b
10a+b=6+4(a+b)
So, putting this in a workable form
a-b=-3
6a-3b=6
Solved by pluggable solver: Linear System solver (using determinant)
Solve:
+system%28+%0D%0A++++1%5Ca+%2B+-1%5Cb+=+-3%2C%0D%0A++++6%5Ca+%2B+-3%5Cb+=+6+%29%0D%0A++

Any system of equations:


has solution

or



(a=5, b=8}