SOLUTION: Hi Becky walks to the stadium which is 580m way from her house for 20min . She walks back to her house using the same route at a speed of 20m per minute. What is her average spe

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Question 1185644: Hi
Becky walks to the stadium which is 580m way from her house for 20min . She walks back to her house using the same route at a speed of 20m per minute.
What is her average speed.
Thanks

Found 3 solutions by josgarithmetic, Alan3354, MathTherapy:
Answer by josgarithmetic(39616) About Me  (Show Source):
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Going, 580%2F20 or 29 meters per minute
Returning, 580%2Ameters%2A%281%2F20%29%28minutes%2Fmeters%29=29 minutes


total distance, 2%2A580=1160 meters
total time 20%2B29=49 minutes

Average speed, %281160%2F49%29%28meters%2Fminute%29
23.7 meters per minute

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Becky walks to the stadium which is 580m way from her house for 20min . She walks back to her house using the same route at a speed of 20m per minute.
What is her average speed.
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Avg speed going is 580/20 = 29 m/min
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Avg speed for round trip = 2*29*20/(29+20) =~ 23.67 m/minute
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I don't recommend memorizing formulas generally, but the avg speed for a round trip is 2*v1*v2/(v1+v2).
This is the same as for parallel flows, parallel resistors, parallel work, etc. except for the factor of 2.

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
Becky walks to the stadium which is 580m way from her house for 20min . She walks back to her house using the same route at a speed of 20m per minute.
What is her average speed.
Thanks


Total Distance: 2(580) = 1,160 m


Time spent going: 20 minutes
Time spent returning: matrix%281%2C4%2C+580%2F20%2C+%22=%22%2C+29%2C+minutes%29
Total Time spent on trip: 20 + 29 = 49 minutes