SOLUTION: A student in a chemistry laboratory wants to form a 32 ml mixture of 2 solutions to contain 30% acid. Solution A contains 42% acid and solution B contains18% acid. How many ml o

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Question 1182613: A student in a chemistry laboratory wants to form a
32 ml mixture of 2 solutions to contain 30% acid.
Solution A contains 42% acid and solution B
contains18% acid. How many ml of each solution
must be used?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Use 42% acid and 18% acid solutions to make 32 mL. of 30%.

If v mL. of 42%, then to account for pure acid,
42v%2B18%2832-v%29=30%2A32
and solve for v.


Be aware that %2842%2B18%29%2F2=30, so the student will need 16 mL. of each of the starting solutions of acid.