SOLUTION: Find the distance between the point (3,5) and the line y= 3/2x + 5 given the slope of the line perpendicular to the given line is -2/3 and the equation of the line through (3,5) an

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Question 1179770: Find the distance between the point (3,5) and the line y= 3/2x + 5 given the slope of the line perpendicular to the given line is -2/3 and the equation of the line through (3,5) and perpendicular to y= 3/2x + 5 is y= -2/3 x -3
Found 2 solutions by josgarithmetic, ewatrrr:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Find the point that y=%283%2F2%29x%2B5 intersects with cross%28y=-%282%2F3%29x-3%29. Use the Distance Formula to find distance from this point and (3,5).


The line of slope -2%2F3 with the point (3,5):
y-5=%28-2%2F3%29%28x-3%29
y-5=-2x%2F3%2B2
y=-2x%2F3%2B7
.
.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi
the equation of the line through (3,5) and perpendicular to y= (3/2)x + 5 
is y=(-2/3 )x +7
 y = (-2/3)x  -3 does not include (3,5)
Check your info and repost if you wish.



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