SOLUTION: From a tank 1/3 full of water, 21 liters loss due to leaking, 1/2 water remained. Determine capacity of tank. c = capacity 1/3c - 21 = .5c .66c - 21 = .5c Not sure if

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Question 1177520: From a tank 1/3 full of water, 21 liters loss due to leaking, 1/2 water remained. Determine capacity of tank.
c = capacity
1/3c - 21 = .5c
.66c - 21 = .5c
Not sure if correct steps.

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
Unsure your description; maybe rewrite it so nothing is unclear/ambiguous/imprecise.

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From a tank 1/3 full of water, 21 liters loss due to leaking, 1/2 water remained. Determine capacity of tank.
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c, the capacity
c%2F3 liters to begin

c%2F3-21, liters in tank due to leakage


"Half the water remained" - Is that, half of the initial amount of water remained?
c%2F3-21=%281%2F2%29%28c%2F3%29----------this would seem to represent that description. Simplify and solve for c.






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Based on the private message, solving the above equation will also show capacity was 126 liters.

Answer by MathTherapy(10557) About Me  (Show Source):
You can put this solution on YOUR website!

From a tank 1/3 full of water, 21 liters loss due to leaking, 1/2 water remained. Determine capacity of tank.
c = capacity
1/3c - 21 = .5c
.66c - 21 = .5c
Not sure if correct steps.
Tank can't be 1%2F3 full (less than 1%2F2 full), and lose 21 L to then be 1%2F2 full. Doesn't make sense!