Question 1177095: Hi
A V and W had a total of 510 stickers. The ratio of A to V stickers was 6:7 at first. After A and V each gave away half of their stickers the 3 had 345 stickers left. How many did W have at first.
Thank you
Found 2 solutions by Theo, ikleyn:
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! A + V + W = 510
510 - 1/2 * (A + V) = 345
this means that 1/2 * (A + V) = 165, because 510 - 165 = 345.
this means that (A + V) = 330
since A + V + W = 510, then:
W must be equal to 510 - 330 = 180.
that should be your answer.
the additional information that A/V = 6/7 looks like it was extraneous, as it does not appear that it had anything to do with solving the problem.
Answer by ikleyn(52818)  (Show Source):
You can put this solution on YOUR website! .
A V and W had a total of 510 stickers. The ratio of A to V stickers was 6:7 at first. After A and V each
gave away half of their stickers the 3 had 345 stickers left. How many did W have at first.
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As a continuation of the solution by @Theo.
===============================================
In this problem, the imposed conditions CONTRADICT each to the other, so such integer numbers,
satisfying the imposed conditions, DO NOT EXIST.
Indeed, if the sum A + V = 330, as @Theo correctly found in his solution, then the ratio of A to V stickers CAN NOT be 6:7,
since there are no such integers A and V with the sum of 330 and with the ratio 6:7.
Thus this problem is a FAKE, good only for re-cycling.
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