SOLUTION: 20 men can dig a tank 40 feet long and 30 feet broad and 10 feet deep in 25 days. In how many days will 60 men dig a tank 90 feet long, 60 feet broad and 20 feet deep?
Algebra ->
Customizable Word Problem Solvers
-> Misc
-> SOLUTION: 20 men can dig a tank 40 feet long and 30 feet broad and 10 feet deep in 25 days. In how many days will 60 men dig a tank 90 feet long, 60 feet broad and 20 feet deep?
Log On
Question 1171749: 20 men can dig a tank 40 feet long and 30 feet broad and 10 feet deep in 25 days. In how many days will 60 men dig a tank 90 feet long, 60 feet broad and 20 feet deep? Found 2 solutions by Solver92311, ikleyn:Answer by Solver92311(821) (Show Source):
Find the volume of the 40 by 30 by 10 hole, and then divide that by 25. That gives you the number of cubic feet that 20 men can dig in one day. Multiply that by 3 to get the number of cubic feet that 60 men can dig in one day. Divide the volume of the big tank by the number of cubic feet that 60 men can dig in one day to find the number of days for 60 men to dig the big tank.
John
My calculator said it, I believe it, that settles it
From
I > Ø
You can put this solution on YOUR website! .
20 men can dig a tank 40 feet long and 30 feet broad and 10 feet deep in 25 days.
In how many days will 60 men dig a tank 90 feet long, 60 feet broad and 20 feet deep?
~~~~~~~~~~~~~~~~
In first scenario, the volume of the tank is 40*30*10 = 12000 cubic feet.
and the rate of work is = 24 cubic feet per day per man.
In second scenario, the volume of the tank is 90*60*20 = 108000 cubic feet.
and the rate of work is = cubic feet per day per man, where x is an unknown number of days.
Assuming that the rate of work is the same in both scenarios, we have this equation
24 = ,
which implies x = = 75 days. ANSWER
