SOLUTION: Let b0, b1, b2, be the sequence defined by the explicit formula bn = C · 5^n + D(−4)^n for each integer n ≥ 0, where C and D are real numbers. (a) Find C and D so that

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Question 1167598: Let
b0, b1, b2, be the sequence defined by the explicit formula
bn = C · 5^n + D(−4)^n for each integer n ≥ 0,
where C and D are real numbers.
(a)
Find C and D so that
b0 = 0
and
b1 = −9.
b) Find C and D so that
b0 = 4
and
b1 = 11.
c)What is
b2 in this case?

Answer by Resolver123(6) About Me  (Show Source):
You can put this solution on YOUR website!
(a) b%5Bn%5D+=+c%2A5%5En+%2B+d%2A%28-4%29%5En for n%3E=0
means that b%5B0%5D+=+c%2A5%5E0+%2B+d%2A%28-4%29%5E0=c%2Bd=0, by hypothesis, after direct substitution.
Also, inserting n=1 into the formula gives b%5B1%5D+=+c%2A5%5E1+%2B+d%2A%28-4%29%5E1=-9.
Hence, 5c-4d=-9.
From c + d = 0, we get d = -c.
Substituting this into the equation 5c - 4d = -9 gives 5c - 4(-c) = 5c+4c = -9,
or 9c = -9, or c = -1.
Therefore, c = -1, and d = -(-1) = 1.
(b) Similarly, b%5Bn%5D+=+c%2A5%5En+%2B+d%2A%28-4%29%5En gives b%5B0%5D+=+c%2A5%5E0+%2B+d%2A%28-4%29%5E0=c%2Bd=4, or c + d = 4, or d = 4 - c. Also, b%5B1%5D+=+c%2A5%5E1+%2B+d%2A%28-4%29%5E1=11, or 5c - 4d = 11.
Substituting, 5c - 4(4 - c) = 11, or 5c - 16 + 4c = 11.
This gives 9c = 27, or c = 3, which consequently gives d = 4 - 3 = 1.
(c) From part (b), we get b%5Bn%5D+=+3%2A5%5En+%2B+%28-4%29%5En, so that b%5B2%5D+=+3%2A5%5E2+%2B+%28-4%29%5E2=3%2A25%2B16+=+75%2B16=91