Question 1163877: Two balanced 4 sided-dice, each with faces labeled by 1, 2, 3 and4.
if Ali plays a game where he tosses two balanced 4 sided-dice
He wins 3 points if the sum is 6.
He wins 2 points if the sum is greater than 6.
He loses 1 point if the sum is less than 6.
Find the probability distribution sum.
Answer by solver91311(24713)   (Show Source):
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Sum Ways
2 1,1
3 1,2 2,1
4 1,3 2,2 1,3
5 1,4 2,3 3,2 4,1
6 2,4 3,3 4,2
7 3,4 4,3
8 4,4
There are 16 possible combinations, 6 three ways, more than 6 three ways, and less than 6 ten ways. So if X is the of points won:
X P(X) xP(x)
3 0.375 1.05
2 0.375 0.75
-1 0.675 -0.675
∑xP(x) = 1.125
John
My calculator said it, I believe it, that settles it
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