SOLUTION: The Blumin Garden Club planned to give their president a gift of appreciation costing $120 and to divide the cost evenly. In the meantime, 5 members dropped out of the club. If it

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Question 1157084: The Blumin Garden Club planned to give their president a gift of appreciation costing $120 and to divide the cost evenly. In the meantime, 5 members dropped out of the club. If it now costs each of the remaining members $2 more than originally planned, how many members initially participated in the gift buying?
Found 4 solutions by Boreal, ikleyn, josgarithmetic, mananth:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
they had x people who each gave 120/x dollars
now they have x-5 people who give 120/(x-5), and that is $2 more than the first
so 120/(x-5)=(120/x)+2=(120+2x)/x for common denominator. Cross-multiply
120x=(x-5)(120+2x)=120x+2x^2-600-10x
120x=120x_2x^2-10x-600, and the 120x on each side cancel
2x^2-10x-600=0
x^2-5x-300=0
(x-20)(x+15)=0
x=20, only positive value
20 people, each giving $6
now 15 people, each giving $8.
20 is the answer.

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

If n is the value under the question, then the equation to find n is THIS


    120%2F%28n-5%29 - 120%2Fn = 2.


Its solution is  n = 20  (I solved the equation MENTALLY).


You may deduce it to the standard quadratic equation form and solve formally.

Solved.

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
PRICE%2AQUANTITY=COST

-
                        PRICE      QUANTITY   COST

MEMBERS AS PLANNED      120/n        n        120

FIVE FEWER MEMBERS      120/(n-5)    n-5      120

DIFFERENCE               2

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
let number of members be x
each member contributes 120/x
5 members leave
each contributes 120/(x-5)
+120%2F%28x-5%29-120%2Fx+=2
%28120x+-120%28x-5%29%29%2Fx%28x-5%29+=+2
+120x%2B600-120x%29+=+2x%5E2-10x
2x^2-10x-600=0
x^2-5x -300 =0 ( divide by 2)
(x-20)(x+15)=0
x=20 OR -15 ignore negative
20 members originally.