SOLUTION: Find the equation of the line tangent to the curve at the point defined by the given value of t.
{{{x=16sint}}}, {{{y=4cost}}}, {{{t=pi/4}}}
Algebra ->
Customizable Word Problem Solvers
-> Misc
-> SOLUTION: Find the equation of the line tangent to the curve at the point defined by the given value of t.
{{{x=16sint}}}, {{{y=4cost}}}, {{{t=pi/4}}}
Log On
You can put this solution on YOUR website! Find the equation of the line tangent to the curve at the point defined by the given value of t. , ,
--------- ---> @ pi/4 = 8sqrt(2) ---> @ pi/4 = 2sqrt(2)
dx/dt = 16cos(t) ---> @ pi/4 = 8sqrt(2)
dy/dt = -4sin(t) ---> @ pi/4 = -2sqrt(2)
-----
dy/dx = -sin(t)/(4cos(t)) = -tan(t)/4
@pi/4: dy/dx = -1/4
============
