SOLUTION: Dr. Don offers tutoring service for college students. He charges $40 as a fixed rate for the first hour plus $20 for each additional hour. What is the minimum and maximum number of
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Question 1154861: Dr. Don offers tutoring service for college students. He charges $40 as a fixed rate for the first hour plus $20 for each additional hour. What is the minimum and maximum number of hours of tutoring a student can get if he or she can afford to spend between $140 and $200? ( express answer as an inequality) Found 4 solutions by mananth, josgarithmetic, MathTherapy, ikleyn:Answer by mananth(16949) (Show Source):
You can put this solution on YOUR website! --------------------------------------------
He charges $40 as a fixed rate for the first hour plus $20 for each additional hour.
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TIME,x COST, y
0 0
1 40
2 40+20
3 40+2*20
4 40+3*20
x 40+20(x-1)
For x=0 y=0
For x=1 y=40
For x more than 1 y=20(x-1)+40
The minimum time for cost $140, --------------six hours of tutoring
The max time if cost $200,
... you can figure this ....
You can put this solution on YOUR website! Dr. Don offers tutoring service for college students. He charges $40 as a fixed rate for the first hour plus $20 for each additional hour. What is the minimum and maximum number of hours of tutoring a student can get if he or she can afford to spend between $140 and $200? ( express answer as an inequality)
Let each hour of tutoring be h
Then the cost equation is: f(h) = 20(h - 1) + 40
f(h) = 20h - 20 + 40
f(h) = 20h + 20
Therefore, to get number of hours of tutoring for costs between $140 and $200, we have: --- Subtracting 20 --------- Dividing by 20
As seen, minimum and maximum number of hours she can afford are 6 and 9, respectively.
You can put this solution on YOUR website! .
Dr. Don offers tutoring service for college students. He charges $40 as a fixed rate for the first hour plus $20
for each additional hour. What is the minimum and maximum number of hours of tutoring a student can get if he or she
can afford to spend between $140 and $200? ( express answer as an inequality)
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The final answer in the post by @mananth is given in incorrect form.
I came to fix it.
f(h) = 40 + 20(h-1) <<<---=== first hour is presented by the addend '40'
140 <= 40 + 20(h-1) <= 200
Subtract 40 from all the terms
100 <= 20(h-1) <= 160
Divide by 20 all the terms
5 <= h-1 <= 8
Hence, 6 <= h <= 9. <<<---=== ANSWER
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As the problem is worded, it admits different interpretations,
which is a bad style writing Math.
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