Let x be the initial volume of water in Tank B. Then initial volume in Tank A was 4x. The equation is 4x - 1.485 = x + 1.485 liters 3x = 1.485 + 1.485 = 2.970 liters x = 2.970/3 = 0.99 liters ANSWER. At the end, tank A contained 4x-1.485 = 4*0.99-1.485 = 2.475 liters = 2 liters and 475 milliliters. At the end, tank B contained the SAME amount of water, as tank A contained at the end, i.e. 2 liters and 475 milliliters.