SOLUTION: Solve for x: (cx + d) / (a) / (cx) / (d) = (2d) / (a) Not sure how to continue.

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Question 1134359: Solve for x:
(cx + d) / (a) / (cx) / (d) = (2d) / (a)
Not sure how to continue.

Found 4 solutions by MathLover1, Boreal, josmiceli, MathTherapy:
Answer by MathLover1(20849) About Me  (Show Source):
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
(cx+d)/a
-------
(cx/d) = 2d/a

multiply both sides by a
(cx+d)/cx/d=2d
This is d(cx+d)/cx=2d
d will cancel
(cx+d)/cx=2
cx+d=2cx
subtract cx from both sides
d=cx
x=d/c



Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+%28+c%2Ax+%2B+d+%29+%2F%28++a+%2F+%28%28c%2Ax%29+%2F+d%29+%29+=+%28+2d+%29%2F+a+
+%28+c%2Ax+%2B+d+%29+%2F+%28%28+a%2Ad+%29+%2F+%28+c%2Ax+%29%29+=+%282d%29+%2F+a+
+%28%28+c%2Ax+%2B+d+%29%2A%28+c%2Ax+%29%29+%2F+%28+a%2Ad+%29+=+%28+2d+%29%2Fa+
+%28+c%2Ax+%2B+d+%29%2A%28+c%2Ax+%29+=+%28+a%2Ad+%29%2A%282d%2Fa+%29+
+c%5E2%2Ax%5E2+%2B+c%2Ad%2Ax+=+2d%5E2+
+%28+c%5E2+%29%2Ax%5E2+%2B+%28+c%2Ad+%29%2Ax+-+2d%5E2+=+0+
+a%2Ax%5E2+%2B+b%2Ax+%2B+c+=+0+ use this form
+a+=+c%5E2+
+b+=+c%2Ad+
+c+=+-2%2Ad%5E2+
+x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+


+x+=+%28-c%2Ad+%2B-+sqrt%28+9%2A%28c%2Ad%29%5E2+%29%29%2F%282%2Ac%5E2%29+
+x+=+%28+-c%2Ad+%2B-+%28+3%2Ac%2Ad+%29+%29%2F+%28+2%2Ac%5E2+%29+
+x+=+-d%2F%282%2Ac%29+%2B+%283%2F2%29%2A%28+d%2Fc+%29+
+x+=+%28+d%2Fc+%29%2A%28+%283%2F2%29+-+%281%2F2%29+%29+
+x+=+d%2Fc+
and, the other root:
+x+=+-%281%2F2%29%2A%28d%2Fc%29+-+%283%2F2%29%2A%28+d%2Fc%29+
+x+=+-2%2A%28+d%2Fc%29+
You can plug these results back into original equation to check
Definitely get another opinion if needed

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
(cx + d) / (a) / (cx) / (d) = (2d) / (a)
Not sure how to continue.
If matrix%281%2C3%2C+%28%28cx+%2B+d%29%2Fa%29%2F%28cx%2Fd%29%2C+%22=%22%2C+2d%2Fa%29, then:
matrix%281%2C5%2C+%28cx+%2B+d%29%2Fa%2C+%22%2A%22%2C+d%2Fcx%2C+%22=%22%2C+2d%2Fa%29
matrix%281%2C3%2C+d%28cx+%2B+d%29%2Facx%2C+%22=%22%2C+2d%2Fa%29
------ Cancelling GCF, d in numerator, and GCF, a in denominator
2cx = cx + d ------ Cross-multiplying
2cx - cx = d
cx = d
highlight_green%28matrix%281%2C3%2C+x%2C+%22=%22%2C+d%2Fc%29%29