SOLUTION: (m + n) / (m - n) + (m - n) / (m + n) Find the sum. Not sure how to continue.

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Question 1133895: (m + n) / (m - n) + (m - n) / (m + n)
Find the sum.

Not sure how to continue.

Found 2 solutions by algebrahouse.com, MathTherapy:
Answer by algebrahouse.com(1659) About Me  (Show Source):
You can put this solution on YOUR website!
(m + n)/(m - n) + (m - n)(m + n)
(m + n)(m + n)/(m + n)(m - n) + (m - n)(m - n)/(m + n)(m - n) {got common denominator of (m + n)(m - n)}
= (m² + 2mn + n²)/(m + n)(m - n) + (m² - 2mn + n²)/(m + n)(m - n) {multiplied in numerators}
= (2m² + 2n²)/(m + n)(m - n) {combined numerators over common denominator}

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

(m + n) / (m - n) + (m - n) / (m + n)
Find the sum.

Not sure how to continue.
%28m+%2B+n%29%2F%28m+-+n%29+%2B+%28m+-+n%29%2F%28m+%2B+n%29
%28%28m+%2B+n%29%28m+%2B+n%29+%2B+%28m+-+n%29%28m+-+n%29%29%2F%28m+%2B+n%29%28m+-+n%29 ------- Multiplying each expression by LCD, (m - n)(m + n)
<======= CORRECT ANSWER