SOLUTION: Points (4, 5) and (10, 5) are vertices of a rectangle. The length of the rectangle is twice the width. The other vertices are located at (4, ___ ) and (10, ___ ). What could

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Question 1132391: Points (4, 5) and (10, 5) are vertices of a rectangle.
The length of the rectangle is twice the width.
The other vertices are located at (4, ___ ) and (10, ___ ). What could these ordered pairs be?

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
Points (4, 5) and (10,+5) are vertices of a rectangle.
The length of the rectangle is twice the width.
The other vertices are located at (4, ___ ) and (10, ___ ). What could these ordered pairs be?
The length of the rectangle is equal to distance between given points:
L=sqrt%28%2810-4%29%5E2%2B%285-5%29%5E2%29
L=sqrt%286%5E2%2B0%5E2%29
L=sqrt%2836%29
L=6
=> then the width is W=3
The other vertices are located 3 units above or below given points.
(4, 5%2B3) and (10,+5%2B3)
or
(4, 5-3) and (10,+5-3)

=> the other vertices are located at (4, 2) and (10, 2) or at (4, 8) and (10,+8)