SOLUTION: If s = t^3-5t^2+5t-3, when will the velocity be at 2?

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Question 1119869: If s = t^3-5t^2+5t-3, when will the velocity be at 2?
Found 2 solutions by Boreal, greenestamps:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
velocity is ds/dt
ds/dt (t^3-5t^2+5t-3) is 3t^2-10t+5
when s=2, velocity will be -3
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E3-5x%5E2%2B5x-3%29

Answer by greenestamps(13198) About Me  (Show Source):
You can put this solution on YOUR website!


s = t^3-5t^2+5t-3

v = ds/dt = 3t^2-10t+5

Solve to find when v = 2:

3t^2-10t+5 = 2
3t^2-10t+3 = 0
(3t-1)(t-3) = 0

The velocity will be 2 when t=1/3 and when t=3.

A graph of the velocity function, showing that v=2 at t=1/3 and at t=3:

graph%28400%2C400%2C-2%2C4%2C-5%2C10%2C3x%5E2-10x%2B5%2C2%29