SOLUTION: A woman bought 36 basket of oranges, each containing 150 oranges. Out of the the total number 72 went bad. She sold the rest at 2 for ¢300.00 and made a profit ¢16,200.00. Find the

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: A woman bought 36 basket of oranges, each containing 150 oranges. Out of the the total number 72 went bad. She sold the rest at 2 for ¢300.00 and made a profit ¢16,200.00. Find the      Log On

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Question 1117571: A woman bought 36 basket of oranges, each containing 150 oranges. Out of the the total number 72 went bad. She sold the rest at 2 for ¢300.00 and made a profit ¢16,200.00. Find the cost of one basket of oranges
Answer by ikleyn(52852) About Me  (Show Source):
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In all, there were 36*150 oranges initially.


Out of the total, 72 went bad; the rest is 36*150-72 = 5328.


She sold 5328 for c(300/2) each and got c(300/2)*5328 = c799200.


Her profit was c16200 - hence, she bought originally for  c799200 - c16200 = c78300.


The cost of one basket was  78300%2F36 = c21750.

Solved.