SOLUTION: Hi steve and andrew had $540 altogether. Steve gave 1/7 of his money to andrew. In return andrew gave 1/4 of the total amount he had to steve. Then they had both an equal amount

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Question 1109796: Hi
steve and andrew had $540 altogether. Steve gave 1/7 of his money to andrew. In return andrew gave 1/4 of the total amount he had to steve. Then they had both an equal amount of money. How much did steve have at first.
thanks
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
Let s and a be steve and andrew, respectively. Then s+a=540. If steve gives 1/7 of his money to andrew, and andrew gives 1/4 of his money to steve, leaving them with equal amounts of money. So:
(6/7)s=(3/4)a
6s/7=3a/4
24s=21a
s+a=540
24s-21a=0
21s+21a=11340
45s=11340
s=252
a=288
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