Use cross-multiplication to solve.
How do I get rid of the 2 to use cross-multiplication? Non-homework. Found 2 solutions by rothauserc, Boreal:Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! (3x/2) - (1/3) = 2
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we use 6 which is a common multiple of 3 and 2
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(3(3x)/6) -2/6 = 12/6
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(9x/6) -(2/6) = 12/6
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9x/6 = 14/6
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cross multiply fractions
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54x = 84
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x = 84/54 = 14/9
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check answer
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(3(14/9)/2) - (1/3) = 2
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(42/18) - (6/18) = 2
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36/18 = 2
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2 = 2
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answer checks
:
You can put this solution on YOUR website! 3x/2-(1/3)=2
3x/2=2+(1/3)=(7/3); I added 1/3 to both sides. 2= 6/3, so 2 + (1/3)=7/3.
now cross-multiply
9x=14
x=14/9
check
3(14/9)/2-1/3=42/9 divided by 2 -1/3
That is 42/18-1/3
that is 42/18-6/18=36/18=2