SOLUTION: Jen butler has been pricing speed pass train fares for a group trip to New York. Three adults and four children must pay $101. Two adults and three children must pay $72. Find the

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Jen butler has been pricing speed pass train fares for a group trip to New York. Three adults and four children must pay $101. Two adults and three children must pay $72. Find the       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1099159: Jen butler has been pricing speed pass train fares for a group trip to New York. Three adults and four children must pay $101. Two adults and three children must pay $72. Find the price of the abuts ticket and the price of a child's ticket.
Answer by ikleyn(52879) About Me  (Show Source):
You can put this solution on YOUR website!
.
3A + 4C = 101,     (1)
2A + 3C =  72.     (2)


Multiply eq(1) by 2 (both sides). Multiply eq(2) by 3 (both sides).  You will get

6A + 8C = 202,     (3)
6A + 9c = 216.     (4)


Subtract eq(4) from eq(3) (both sides). You will get

C = 216 - 202 = 14.


Now from eq(1)  A = %28101-4%2A14%29%2F3 = 15.


Answer.  Adult ticket price is $15.  Children ticket price is $14.


On tickets, see the lessons
    - Using systems of equations to solve problems on tickets
    - Three methods for solving standard (typical) problems on tickets
in this site.