SOLUTION: two numbers are in the ratio 2 to 7 and their product is 126. what is the larger number?

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Question 1099035: two numbers are in the ratio 2 to 7 and their product is 126. what is the larger number?

Found 3 solutions by KMST, ikleyn, MathTherapy:
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
x= the larger number
The other number, n , is such that
n%2Fx=2%2F7 , so n=%282%2F7%29x
The sum of those two numbers is
x%2B%282%2F7%29x=126
%281%2B2%2F7%29x=126
%289%2F7%29x=126
x=126%2A7%2F9
x=highlight%2898%29

Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.
You may consider another logic/solution.


If the numbers are in the ratio 2 to 7, it means that one number is 2x, while another number is 7x, where x is an unknown factor.


Then the product of these numbers is  (2x)*(7x) = 14x^2.

At the same time, the product is 126, according to the condition.  


It gives you an equation  14x^2 = 126.


Hence,  x^2 = 126%2F14 = 9.


It implies  x = +/- sqrt%289%29 = +/- 3.


If x = 3,   then your answer is: the two numbers are  2*3 = 6  and  7*3 = 21.
                          The greatest of the two numbers is 21.


If x = -3,  then your answer is: the two numbers are  2*(-3) = -6  and  7*(-3) = -21.
                          In this case the greatest of the two numbers is -6.


Answer.  There are two answers to the problem's question: -6  and  21.


Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

two numbers are in the ratio 2 to 7 and their product is 126. what is the larger number?
Correct answer: highlight_green%2821%29