SOLUTION: On the opening night of a play at a local​ theatre, 990 tickets were sold for a total of  ​$9858. Adult tickets cost ​$13 each.​ Children's tick

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Question 1094425: On the opening night of a play at a local​ theatre, 990 tickets were sold for a total of  ​$9858. Adult tickets cost ​$13 each.​ Children's tickets cost ​$9 ​each, and senior citizen tickets cost ​$5 each. If the combined number of children and adult tickets exceeded twice the number of senior citizen tickets by 222​, then how many tickets of each type were​ sold?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = number of adult tickets sold
Let +b+ = number of children's tickets sold
Let +c+ = number of senior tickets sold
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(1) +a+%2B+b+%2B+c+=+990+
(2) +13a+%2B+9b+%2B+5c+=+9858+
(3) +a+%2B+b+=+2c+%2B+222+
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There are 3 equations and 3 unknowns, so it's solvable
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(3) +a+%2B+b+-+2c+=+222+
Subtract (3) from (1)
(1) +a+%2B+b+%2B+c+=+990+
(3) +-a+-+b+%2B+2c+=+-222+
-----------------------------
+3c+=+768+
+c+=+256+
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(2) +13a+%2B+9b+%2B+5%2A256+=+9858+
(2) +13a+%2B+9b+%2B+1280+=+9858+
(2) +13a+%2B+9b+=+8578+
and
(1) +a+%2B+b+%2B+c+=+990+
(1) +a+%2B+b+%2B+256+=+990+
(1) +a+%2B+b+=+734+
----------------------------
Multiply both sides of (1) by +9+
and subtract (1) from (2)
(2) +13a+%2B+9b+=+8578+
(1) +-9a+-+9b+=+-6606+
--------------------------
+4a+=+1972+
+a+=+493+
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and
(3) +a+%2B+b+-+2c+=+222+
(3) +493+%2B+b+-+2%2A256+=+222+
(3) +493+%2B+b+-+512+=+222+
(3) +b+-+19+=+222+
(3) +b+=+241+
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The number of adult tickets sold was 493
The number of children's tickets sold was 241
The number of senior tickets sold was 256
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Check answers
(1) +a+%2B+b+%2B+c+=+990+
(1) +493+%2B+241+%2B+256+=+990+
(1) +990+=+990+
You can check (2) and (3)
Get another opinion if needed