Question 1092628: A rock is thrown upward with a velocity of 12 meters per second from the top of a 25 meter high cliff, and it misses the cliff on the way back down. When will the rock be 33 meters from the water, below? Round your answer to two decimal places.
Answer by jorel1380(3719)   (Show Source):
You can put this solution on YOUR website! The equation for the rock, relating it's height h to its' time (t), would be:
h(t)=-4.9tē+12t+25. So, to get the time when the rock is 33 feet above the water, we have:
33=-4.9tē+12t+25 or
4.9tē-12t+8=0
Then, solve for t
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