SOLUTION: The width of a rectangle is 12 units less than its length. If you add 30 units to both the length and the width, you double the perimeter. Find the width and the length of the orig

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Question 1092493: The width of a rectangle is 12 units less than its length. If you add 30 units to both the length and the width, you double the perimeter. Find the width and the length of the original rectangle.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39613) About Me  (Show Source):
You can put this solution on YOUR website!
Dimensions of original rectangle: x and x-12
Perimeter of original rectangle: 2x+2(x-12)

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Adding 30 units to both dimensions:
2%28x%2B30%29%2B2%28x-12%2B30%29=2%282x%2B2%28x-12%29%29
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x%2B30%2Bx%2B18=2x%2B2%28x-12%29
2x%2B48=2x%2B2x-24
48=2x-24
24=x-12
x=36

Original Rectangle:
Length, 36 units
Width, 24 units

Answer by MathTherapy(10549) About Me  (Show Source):
You can put this solution on YOUR website!
The width of a rectangle is 12 units less than its length. If you add 30 units to both the length and the width, you double the perimeter. Find the width and the length of the original rectangle.